Solved Solve Th 1 Elimination 2x Y 5 3x Y 10 E Chegg Com
NCERT Solutions for Class 10 Maths Chapter 3 Exercise 34 Question 1 Summary On solving the pair of equations by the elimination method and the substitution method we get x, y as (i) x y = 5 and 2x 3y = 4 where, x = 19/5, y = 6/5 , (ii) 3x 4y = 10 and 2x 2y = 2 where, x = 2, y = 1 , (iii) 3x 5y 4 = 0 and 9x = 2y 7 where, x = 9/13, y = 5/13, (iv) x/2 2y/3 = 1 and x y/3 To solve the system of equations, use elimination The equations are in standard form and the coefficients of m are opposites Add { n m = 39 n − m = 9 _ 2 n = 48 Solve for n n = 24 Substitute n=24 into one of the original n m = 39 equations and solve form 24 m = 39 m = 15 Step 6 Check the answer
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The elimination method calculator-Hence, Solution is x=2 , y=−3 By Substitution Method Expressing x in terms of y from equation (i), we have x= 3−6−4y Substituting the value of x in equation (ii) from equation (i), we get 3×( 3−6−4y )−y=9 ⇒−6−4y−y=9 ⇒−6−5y=9 ⇒−5y=96=15 ∴y= −515Web & Mobile subscription
Show Graphically That The System Of Linear Equations 2x 3y 5 6y 4x 3 Youtube
We have two linear equations (to be solved by elimination method) 3x −4y = 9 2x 3y = 7 Multiply first eq by −2 and second by 3 −6x 8y = −18 6x 9y = 21 Now we can add both equations and eliminate the unknown x 17y = 3 y = 3 17Suggested Method Reason 5x y = 32 y = x 2 Substitution The value of y can be substituted into the first equation 4x – 3y = –13 7x 3y = –9 Elimination 3y and –3y are opposites and can easily be eliminated using addition 8x 3y = –7 4x y = 4 Elimination y can be eliminated by multiplying the second equation by –31 12x 5y = 7 and 2x 3y 5 = 0 2 x y = 2 and 2x 3y = 4 3 7y 2x 11 = 0 and 3x y 5 = 0 4 3x y 5 = 0 and 2x 7y 11 = 0 5 3x y = 3 and 7x 2y = 6 2x y = 11 and 5x 4y = 1 7 2x 7y = 1 and 4x 3y = 15 8 3x 5y = 1 and 5x 2y = 19 9 5x 8y = 9 and 3y 2x = 4 10 6x 5y = 2 and 5x 6y = 9
Best answer The given equations are 3/x 1/y 9 = 0, ⇒ 3/x 1/y = 9 (i) ⇒ 2/x 3/y = 5 (ii) Putting 1/x = u and 1/y = v, we get 3u – v = 9Step1 The first step is to multiply or divide both the linear equations with a nonzero number to get a common coefficient of any one of the variables in both equations Step2 Add or subtract both the equations such that the same terms will get eliminated3 x 4 y = 9 1 Total value 3 x 2 y = 9 2 add (1) & (2) 2y=18 /2 y=9 plug y in (1) 3x4y=9 3x4(9)=9 3x36=9 3x=27 /3 x=9
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 Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |
Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |
Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |  Rd Sharma Solutions For Class 10 Mathematics Cbse Chapter 3 Pairs Of Linear Equations In Two Variables Topperlearning |
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