Solved Solve Th 1 Elimination 2x Y 5 3x Y 10 E Chegg Com
NCERT Solutions for Class 10 Maths Chapter 3 Exercise 34 Question 1 Summary On solving the pair of equations by the elimination method and the substitution method we get x, y as (i) x y = 5 and 2x 3y = 4 where, x = 19/5, y = 6/5 , (ii) 3x 4y = 10 and 2x 2y = 2 where, x = 2, y = 1 , (iii) 3x 5y 4 = 0 and 9x = 2y 7 where, x = 9/13, y = 5/13, (iv) x/2 2y/3 = 1 and x y/3 To solve the system of equations, use elimination The equations are in standard form and the coefficients of m are opposites Add { n m = 39 n − m = 9 _ 2 n = 48 Solve for n n = 24 Substitute n=24 into one of the original n m = 39 equations and solve form 24 m = 39 m = 15 Step 6 Check the answer
